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A constant force produces maximum velocity `V` on the block connected to the spring of force constant `K` as shown in the fig. When the force constant of spring becomes `4K` the maximum velocity of the block is A. `(V)/(4)`B. `2V`C. `(V)/(2)`D. `V` |
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Answer» Correct Answer - C At maximum, velocity, `F_(n et)=0rArrF=kx` By work energy theorem, `W=DeltaKE` `F_(x)-(1)/(2)Kx^(2)=(1)/(2)mV^(2)-0` `rArr(F^(2))/(2K)=(1)/(2)mV^(2)rArrVprop(1)/(sqrtK)` |
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