A constant power 'P' is applied to a particle of mass 'm'. The displacement of the particle when its velocity increases from v_(1) " to " v_(2) is (ignore friction)

A constant power 'P' is applied to a particle of mass 'm'. The displac

1.	A constant power 'P' is applied to a particle of mass 'm'. The displacement of the particle when its velocity increases from v_(1) " to " v_(2) is (ignore friction)
Answer» Solution :Power P= F.v (ma) v `a= (P)/(MV) rArr v.(dv)/(ds)= (P)/(mv)` `v^(2).dv= (P)/(m)ds " " (P)/(m) UNDERSET(0)overset(s)INT ds= underset(v_(1))overset(v_(2))int v^(2)dv` `(P)/(m).s = (1)/(3) (v_(2)^(3)-v_(1)^(3)) THEREFORE`