A constant power .P. is applied to a particle of mass .m.. The displacement of the particle when its velocity increases from upsilon_(1) to upsilon_(2) is (ignore friction)

A constant power .P. is applied to a particle of mass .m.. The displac

1.	A constant power .P. is applied to a particle of mass .m.. The displacement of the particle when its velocity increases from upsilon_(1) to upsilon_(2) is (ignore friction)
Answer» SOLUTION :Power P = F. `UPSILON = (ma)upsilon` `a=(P)/(m upsilon) rArr upsilon(d upsilon)/(DS)=(P)/(m upsilon)` `upsilon^(2).d upsilon=(P)/(m)" ds" (P)/(m) int_(0)^(s) ds = int_(upsilon_(1))^(upsilon_(2))upsilon^(2).d upsilon` `(P)/(m).s=(1)/(3)(upsilon_(2)^(3)-upsilon_(1)^(3)) "" therefore s=(m)/(3P)(upsilon_(2)^(3)-upsilon_(1)^(3))`