A constant power `P` is applied to a particle of mass `m`. The distance traveled by the particle when its velocity increases from `v_(1)` to `v_(2)` is (neglect friction):A. `(3P)/m(v_(2)^(2)-v_(1)^(2))`B. `m/(3P)(v_(2)^(3)-v_(1)^(3))`C. `m/(3P)(v_(2)^(2)-v_(1)^(2))`D. `m/(3P)(v_(2)-v_(1))`

A constant power `P` is applied to a particle of mass `m`. The distanc

1.	A constant power `P` is applied to a particle of mass `m`. The distance traveled by the particle when its velocity increases from `v_(1)` to `v_(2)` is (neglect friction):A. `(3P)/m(v_(2)^(2)-v_(1)^(2))`B. `m/(3P)(v_(2)^(3)-v_(1)^(3))`C. `m/(3P)(v_(2)^(2)-v_(1)^(2))`D. `m/(3P)(v_(2)-v_(1))`
Answer» Correct Answer - B acceleration `a=P/(mv)` `v(dv)/(dx)=P/(mv)` `int_(0)^(a)dx=m/P int_(v_(1))^(v_(2))v^(2)dv` `S=m/(3p)(v_(2)^(2)-v_(1)^(2))`

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A constant power `P` is applied to a particle of mass `m`. The distance traveled by the particle when its velocity increases from `v_(1)` to `v_(2)` is (neglect friction):A. `(3P)/m(v_(2)^(2)-v_(1)^(2))`B. `m/(3P)(v_(2)^(3)-v_(1)^(3))`C. `m/(3P)(v_(2)^(2)-v_(1)^(2))`D. `m/(3P)(v_(2)-v_(1))`

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