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A constant retarding force of 50 N is applied to a body of mass 20 kg moving initially with a speed of 15 ms-1. How long does the body take to stop? |
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Answer» Here, M = 20 kg, F = 50 (retarding force) As F = mg ⇒ a = F/m = -50/20 = -2.5 ms-2 Also, v = u + at, Here u = 15 ms-1, v = 0 ⇒ 0 = 15 + (-2.5) x t ⇒ t = 6s |
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