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A constant torque acting on a uniform circular wheel changes its angluar momentum from `A_0` to `4 A_0` in `4 s`. The magnitude of this torque is equal to.A. `3 A_0//4`B. `4 A_0`C. `A_0`D. `12 A_0` |
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Answer» Correct Answer - A (a) `tau = (Delta L)/(Delta t) = (4 A_0 - A_0)/(4) = (3 A_0)/(4)` |
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