A constant torque of 20 Nm is exerted bri a pivoted wheel for 10 seconds during which" time' the angular velocity of the wheel changes from 0 to 100 rpm. When the external torque is removed'it is stopped by friction in 100 s. Find (i) the MX of the wheel and (ii) the fiictional torque ?

A constant torque of 20 Nm is exerted bri a pivoted wheel for 10 secon

1.	A constant torque of 20 Nm is exerted bri a pivoted wheel for 10 seconds during which" time' the angular velocity of the wheel changes from 0 to 100 rpm. When the external torque is removed'it is stopped by friction in 100 s. Find (i) the MX of the wheel and (ii) the fiictional torque ?
Answer» SOLUTION :`alpha = omega//t =2PI XX (5//3)//10 = 1.047 "rads"^(-2), I =tau//alpha = 20//1.047 = 19.10 kg m^(2)` , `a.=0 -10.47//10 =-0.1047 rad s^(-1), tau. = Ia. = -0.1047 xx 19.10 = -2 NM`