A container has one mole of monoatomic ideal gas. Each molecule has f degrees of freedom. What is the ratio of gamma=(C_(P))/(C_(V))

A container has one mole of monoatomic ideal gas. Each molecule has f

1.	A container has one mole of monoatomic ideal gas. Each molecule has f degrees of freedom. What is the ratio of gamma=(C_(P))/(C_(V))
Answer» f `f/2` `f/(f+2)` `(f+2)/f` Solution :Energy associated with 1 MOLE of GAS `U=f/2 RT` `C_(v)=f/2 R` `C_(P)=(1+f/2)R` `GAMMA=C_(P)/C_(V)+((1+f/2))/(f/2)=((2+f/2))/((f/2)), gamma =(f+2)/f`