1.

A container has two immiscible liquids P_(1)&P_(2), A capillary tube of radius r is inserted into the liquid so that its bottom reaches upto the denser liquid. The denser liquid in the capillary attains a height .h. from the interface of the liquids, which is equal to column length of lighter liquid. Assume angle of contact to the zero the surface tension of heavier liquid is

Answer»

Solution :APPLY excess PRESSURE concept
`P_(A)=P_(C)=P_(O)+hP_(1)G=P_(B)`
`P_(N)=P_(N)(-2T)/R=P_(0)(-2T)/R,P_(B)=P_(N)+hp_(2)g`


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