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A contract is to be completed in 50 days and 105 men were set to work, each working 8 h a day. After 25 days, 2/5 th of the work is finished. How many additional men be employed, so that the work may be completed on time, each man now working 9 h a day? |
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Answer» 34 `(M_(1) D_(1) T _(1))/W_(1) = (M_(2) D_(2) T_(2))/w_(2)`(by TECHNIQUE 1 ) Given `M_(1) = 105, D_(1) =25, T_(1)=8, W_(1)= 2/5` Now, let the additional men be x. Then, `M_(2)=105 +x,T_(2)=9` `D_(2)=25` And `W_(2) =1 - 2/5 + 3/5` On putting these values in the above formula ` (105xx 25 xx 8)/(2//5) = ((105+x)xx25xx9)/(3//5)` `=(105xx8)/2 =((105+x) xx 9)/3` ` = 105 xx 4 = (105 +x) xx3` `= 105xx4 = 105 xx 3 + 3x` `RARR 3x=105` `therefore x = 35` men |
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