A contributions of both heat (enthalpy) and randomness(entropy) shall be considered to the overall spontaneity of process.When deciding about the spontaneity of a chemical reaction or other process, we define a quantity called the Gibb's energy change (DeltaG). DeltaG=DeltaH-TDeltaS where,DeltaH=Enthalpy change, DeltaS=Entropychange , T=Temperature in kelvin. If DeltaGlt0, Process is spontaneous , DeltaG=0, Process is at equilibrium , DeltaGgt0, Process is non-spontaneous. For the change H_2O(s),(273 K,2 atm)to H_2O(l),(273 K, 2 atm), choose the correct option.

A contributions of both heat (enthalpy) and randomness(entropy) shall

1.	A contributions of both heat (enthalpy) and randomness(entropy) shall be considered to the overall spontaneity of process.When deciding about the spontaneity of a chemical reaction or other process, we define a quantity called the Gibb's energy change (DeltaG). DeltaG=DeltaH-TDeltaS where,DeltaH=Enthalpy change, DeltaS=Entropychange , T=Temperature in kelvin. If DeltaGlt0, Process is spontaneous , DeltaG=0, Process is at equilibrium , DeltaGgt0, Process is non-spontaneous. For the change H_2O(s),(273 K,2 atm)to H_2O(l),(273 K, 2 atm), choose the correct option.
Answer» <P>`DeltaG=0` `DeltaGlt0` `DeltaGgt0` None Solution :`H_2O(s)toH_2O(L)` At P =1 ATM, `DeltaG=0`, there is EQUILIBRIUM at 293 K Hence, as `P uarr`, more `H_2O(l)` is formed.