1.

A converging lens of focal length 5cm is placed at a distance of 20cm from a screen. How far from the lens should an object be placed so as to from its real image on the screen​

Answer»

f = 5 CMU = - 20 cmv = + V (SINCE IMAGE is real)LENS formula : 1/v – 1/u = 1/f1/v – 1/-20 = 1/51/v = 1/5 – 1/20 = (4 – 1)/20 = 3/20V = 6.66



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