1.

A convex refracting surface of radius of curvature `20 cm` separates two media of refractive indices `4//3 and 1.60`. An object is placed in the first medium `(mu = 4//3)` at a distance of `200 cm` from the refracting surface. Calculate the position of image formed.A. `120 cm`B. `240 cm`C. `100 cm`D. `60 cm`

Answer» Correct Answer - B
Using, `- (mu_(1))/(mu) + (mu_(2))/(v) = (mu_(2) - mu_(1))/(R)`
Here, `R = 20 cm, mu_(1) = 4/3 . Mu_(2) = 1.60, u = - 200 cm`
`:. - (4//3)/(-200) + (1.60)/(v) = (1.60 - (4//3))/(20) rArr v = 240 m`


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