A coordiantion complex compound of cobalt has the molecular formula containing four ammonia molecules, one nitro group and two chlorine atoms. A solution of this complex was prepared by dissolving 2.44 g of it in water and making the volume to 200 mL. Excess of AgNO_(3) solution was then added to it and the precipitate of AgCl formed was filtered and dried. The weight of AgCl thus obtained was found to be 1.435 g (Atomic mass of Co=59, Ag=108) The formula of the complex would be

A coordiantion complex compound of cobalt has the molecular formula co

1.	A coordiantion complex compound of cobalt has the molecular formula containing four ammonia molecules, one nitro group and two chlorine atoms. A solution of this complex was prepared by dissolving 2.44 g of it in water and making the volume to 200 mL. Excess of AgNO_(3) solution was then added to it and the precipitate of AgCl formed was filtered and dried. The weight of AgCl thus obtained was found to be 1.435 g (Atomic mass of Co=59, Ag=108) The formula of the complex would be
Answer» `[CO(NH_(3))_(4)(NO_(2))]Cl_(2)` `[Co(NH_(3))_(4)Cl(NO_(2))]Cl` `[Co(NH_(3))_(4)Cl_(2)]NO_(2)` `[Co(NH_(3))_(4)Cl_(2)(NO_(2))]` Solution :Molar mass of `Co(NH_(3))_(4)(NO_(2))Cl_(2)=59+68+46+71=244 g mol^(-1)` `therefore` 2.44 g of the complex `=(2.44)/(244)=0.01` mol. Molar mass of AGCL = 108+35.5=143.5 g `therefore 1.435 g AgCl = (1.435)/(143.5)=0.01` mol This shows that one mole of the complex gives 1 mole of `Cl^(-)` ions in the solution. Hence, the FORMULA of the complex must be `[Co(NH_(3))_(4)Cl(NO_(2))]Cl`.