1.

A coordination compound of cobalt has the molecular formula cotaining five ammonia molecules, one intro group and two chlorine atoms for one cobalt atom. One mole of this compoundproduces three moles of ions in an aqueous solution. The aqueous solution on treatment with an excess of AgNO_(3) gives two moles of AgCl as a precipitate. The formula of this complex would be

Answer»

`[CO(NH_(3))_(4)(NO_(2))Cl][(NH_(3))_(4)Cl]`
`[Co(NH_(3))_(5)Cl][ClNO_(2)]`
`[Co(NH_(3))_(5)(NO_(2))]Cl_(2)`
`[Co(NH_(3))_(5)][(NO)_(2))_(2)Cl_(2)]`

Solution :( C) `[Co(NH_(3))_(5)(NO_(2))]Cl_(2) OVERSET(aq)IFF[Co(NH_(3))_(5)(NO_(2))]^(2+)(aq)+2Cl^(-)(aq)`(no. of ions=3)
`2Ag^(+)+2Cl^(-) to 2AgCl darr `(white).


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