A coordination compound with molecular formula CrCl3.4H2O pr

1.	A coordination compound with molecular formula CrCl3.4H2O precipitates one mole AgCl when excess of AgNO3 is added to 1M solution of the compound. (i) What is the formula of the compound? (ii) What is the ion ratio of the electrolyte corresponding to the conductivity?
Answer» i) Since, we got only one mole AgCl when excess of AgNO₃ is added to 1M solution of the compound. It means only one ionizable chloride ion out side the coordination sphere. Therefore, the formula of the compound will be - [Cr(H₂O)₄ Cl₂]Cl Tetra aqua dichloro chromium (iii) chloride [Cr(H₂O)₄ Cl²] Cl + AgNO3 →[Cr(H₂O)₄Cl₂] NO3 + AgCl\(\downarrow\) ii) [Cr(H₂O)₄Cl₂] Cl gives two ions Cl (Chloride ion) and [Cr(H₂O)₄Cl₂]⁺(Complex ion). In a aqueous solution. Therefore, the ion ratio of the electrolyte corresponding to the conductivity is 1:1

A coordination compound with molecular formula CrCl3.4H2O precipitates one mole AgCl when excess of AgNO3 is added to 1M solution of the compound. (i) What is the formula of the compound? (ii) What is the ion ratio of the electrolyte corresponding to the conductivity?

Answer»

i) Since, we got only one mole AgCl when excess of AgNO₃ is added to 1M solution of the compound. It means only one ionizable chloride ion out side the coordination sphere.

Therefore, the formula of the compound will be -

[Cr(H₂O)₄ Cl₂]Cl

Tetra aqua dichloro chromium (iii) chloride

[Cr(H₂O)₄ Cl²] Cl + AgNO3 →[Cr(H₂O)₄Cl₂] NO3 + AgCl\(\downarrow\)

ii) [Cr(H₂O)₄Cl₂] Cl gives two ions Cl (Chloride ion) and [Cr(H₂O)₄Cl₂]⁺(Complex ion). In a aqueous solution.

Therefore, the ion ratio of the electrolyte corresponding to the conductivity is 1:1

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