A copper block of mass 2.5 kg is heated in a furnace to a temperature of 500^(@)C and then placed on a large ice block. What is the maximum amount of ice that can melt ? (Specific heat of copper =0.39" Jg"^(-1)K"^(-1), heat of fusion of water =335" Jg"^(-1)).

A copper block of mass 2.5 kg is heated in a furnace to a temperature

1.	A copper block of mass 2.5 kg is heated in a furnace to a temperature of 500^(@)C and then placed on a large ice block. What is the maximum amount of ice that can melt ? (Specific heat of copper =0.39" Jg"^(-1)K"^(-1), heat of fusion of water =335" Jg"^(-1)).
Answer» Solution :HEAT obtained by copper block from furnace, `Q=m_(1)CDeltatheta`. . . (1) When heated block is placed on large ice block then `m_(2)` mass of ice starts melting. Required meat for melting, `Q.=m_(2)L.` . . .(2) But `Q=Q.` `:.m_(1)C DELTA theta=m_(2)L.` `:.m_(2)=(m_(1)C Delta theta)/(L.)` `=(2.5xx0.31xx500)/(335)` `=1.455` `~~1.46` `~~1.5` KG