1.

A copper rod 2m long is stretched by 1 mm, the energy stored per unit volume is, `(Y=1.2xx10^(11)N//m^(2))`A. `10xx10^(3)J//m^(3)`B. `20xx 10^(3)J//m^(3)`C. `5xx10^(3)J//m^(3)`D. `15xx10^(3)J//m^(3)`

Answer» Correct Answer - D
`u=(1)/(2) " Stress" xx "Strain"=(1)/(2) Y("Strain")^(2)`


Discussion

No Comment Found

Related InterviewSolutions