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A copper rod 2m long is stretched by 1 mm, the energy stored per unit volume is, `(Y=1.2xx10^(11)N//m^(2))`A. `10xx10^(3)J//m^(3)`B. `20xx 10^(3)J//m^(3)`C. `5xx10^(3)J//m^(3)`D. `15xx10^(3)J//m^(3)` |
Answer» Correct Answer - D `u=(1)/(2) " Stress" xx "Strain"=(1)/(2) Y("Strain")^(2)` |
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