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A copper sphere of mass `2g` contains nearly `2xx10^(22)` atoms. The charge on the nucleus of each atom is `29 e`. What fraction of the electrons must be removed from the sphere to give it a charge fo `+ 2muC` ? |
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Answer» Total number of electrons in the sphere `= 29xx2xx10^(22)` No. of electrons removed `= (q)/(e) = (2xx10^(-6))/(1.6xx10^(-19)) = 1.25xx10^(13)` Fraction of electrons removed `= (1.25xx10^(13))/(29xx2xx10^(22))= 2.16xx10^(-11)` |
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