1.

A copper sphere of mass `2g` contains nearly `2xx10^(22)` atoms. The charge on the nucleus of each atom is `29 e`. What fraction of the electrons must be removed from the sphere to give it a charge fo `+ 2muC` ?

Answer» Total number of electrons in the sphere
`= 29xx2xx10^(22)`
No. of electrons removed
`= (q)/(e) = (2xx10^(-6))/(1.6xx10^(-19)) = 1.25xx10^(13)`
Fraction of electrons removed
`= (1.25xx10^(13))/(29xx2xx10^(22))= 2.16xx10^(-11)`


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