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A copper voltameter is connected in series with a coil of resistance `100Omega`. A steady current flowing in the circuit for 10 minutes, gives a deposit of 0.1 g of copper in the voltameter. Calculate the heat generated in the resistance coil. (ECE of Cu`3.3xx10^(-7)kg//C`) |
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Answer» From first law of electrolysis, m=Zit `rArr I=(m)/(Zt)=(0.1xx10^(-3))/(3.3xx10^(-7)xx600)=0.505A` Heat generated in the resistance coil `=I^(2)Rt=(0.505)^(2)(100) 600=15301 J` |
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