1.

a copper wire has diameter 0.5mm and resistivity of 1.6x10^-8ohm m. (i) what will be the length of this wire to make its resistance 10ohm?.(ii)how much does the resistance changes if the radius is halved?.(iii) how much does the length changes if the radius becomes ¼th?.​

Answer»

R = pl/ar = resistancep = resistivityl = lengtha = areaa = π(0.5/2)*(0.5/2).25π\4r = 10p = 1.6*10^-8l = ra/p(10*.25π\4)/(1.6*10^-8)2.5π\4*1.6*10^-810-8 mmif radius is halved RESISTANCE will b increase by FOUR TIMES if radius become 1/4th resistance will be DOUBLE



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