A cord is wound around the circumference of wheel of radius r. The axis of the wheel is horizontal and MI is I. A weight mg is attached to the end of the cord and falls from rest. After falling through a distance h, the angular velocity of the wheel will be

A cord is wound around the circumference of wheel of radius r. The axi

1.	A cord is wound around the circumference of wheel of radius r. The axis of the wheel is horizontal and MI is I. A weight mg is attached to the end of the cord and falls from rest. After falling through a distance h, the angular velocity of the wheel will be
Answer» `sqrt((2gh)/(I+mr^(2)))` `((2mgh)/(I+mr^(2)))^(1//2)` `((2mgh)/(I+2mr^(2)))^(1//2)` `sqrt(2gh)` SOLUTION :Velocity, `v = r OMEGA` Decrease in GRAVITATIONAL potential energy = INCREASE in kinetic energy `:. mgh=(1)/(2)Iomega^(2)+(1)/(2)mv^(2)=(1)/(2)Iomega^(2)+(1)/(2)m(r omega)^(2)` `:.` Angular velocity, `omega=sqrt((2mgh)/(I+mr^(2)))`.