A cottage industry produces a certain number of toys in a day. The cos

1.	A cottage industry produces a certain number of toys in a day. The cost of production of each toy (in rupees) was found to be 55 minus the number of articles produced in a day. On a particular day, the total cost of production was Rs. 750. If x denotes the number of toys produced that day, form the quadratic equation to find x.
Answer» Given that x denotes the number of toys produced in a day. So, the cost of production of each toy = (55 – x) And, the total cost of production is the product of number of toys produced in a day and cost of production of each toy i.e, x (55 – x) From the question, it’s given that The total cost of production on that particular day is Rs.750 So, ⇒ x (55 – x) = 750 ⇒ 55x – x² = 750 ⇒ x²– 55x + 750 = 0 Thus, the required quadratic equation is x²– 55x + 750 = 0.

A cottage industry produces a certain number of toys in a day. The cost of production of each toy (in rupees) was found to be 55 minus the number of articles produced in a day. On a particular day, the total cost of production was Rs. 750. If x denotes the number of toys produced that day, form the quadratic equation to find x.

Answer»

Given that x denotes the number of toys produced in a day.

So, the cost of production of each toy = (55 – x)

And, the total cost of production is the product of number of toys produced in a day and cost of production of each toy i.e, x (55 – x)

From the question, it’s given that

The total cost of production on that particular day is Rs.750

So,

⇒ x (55 – x) = 750

⇒ 55x – x² = 750

⇒ x²– 55x + 750 = 0

Thus, the required quadratic equation is x²– 55x + 750 = 0.