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A crate of egg is located in the middle of the flat bed of a pick up truck as the truck negotiates an unbanked curve in the road. The curve may be regarded as an arc of circle of radius 35 m. If the coefficient of friction between the crate and the flat bed of the truck is 0.6, the speed with which the truck should turn so that the crate does not slide over the bed is (A) 14.3 m/s (B) 10.3 m/s (C) 12.3 m/s (D) 15.3 m/s |
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Answer» Answer is (A) 14.3 m/s For the crate not to slide, the centripetal force should be \(\frac{mv^2}{r}\) = μmg ∴ v2 = μrg = 0.6 x 35 x 9.8 = 205.8 ∴ v = 14.3 m/s |
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