A cricket ball of mass 150 g has an initial velocity mu=(3hati+4hatj) ms^(-1) and a final velocity v = - (3hat(i) + 4hat(j)) ms^(-1), after being hit. The change in momentum (final momentuminitial momentum) is (in kgms^(-1) )

A cricket ball of mass 150 g has an initial velocity mu=(3hati+4hatj)

1.	A cricket ball of mass 150 g has an initial velocity mu=(3hati+4hatj) ms^(-1) and a final velocity v = - (3hat(i) + 4hat(j)) ms^(-1), after being hit. The change in momentum (final momentuminitial momentum) is (in kgms^(-1) )
Answer» zero `-(0.5 VECI+0.6 vecj)` `-(0.9 vec i+1.2 vecj)` `-5(veci+vec j)veci` Solution :( C) ` - (0.9hat(j )+ 1.2 hat(j ))` Giveninitialvelocity`mu = (3 hat(j )+ 4 hat(j ))` Finalvelocityv = - `(3hat(j)+ 4hat(j ))` Nowchange inmomentum = Finalmomentum- initialmomentum `= m(v-u)` `= (0.15)[-6HAT(j ) - 8 hat(j ))` `= -[0.9hat(j ) + 1.20 hat(j)]`