A cricket ball of mass 150 g is moving with a speed of `12ms^(-1)` and is hit by a bat so that the ball is turned back with velocity of `20ms^(-1)` if duration of contact between bat and ball is 0.01 s then:

A cricket ball of mass 150 g is moving with a speed of `12ms^(-1)` and

1.	A cricket ball of mass 150 g is moving with a speed of `12ms^(-1)` and is hit by a bat so that the ball is turned back with velocity of `20ms^(-1)` if duration of contact between bat and ball is 0.01 s then:
Answer» According to given problem change in momentum of the ball `Deltap=p_(f)-p_(i)=m(v-u)=150xx10^(-3)(20-(-12))=4.8 N-s` So by impulse-momentum theorem, impulse I=change in moment `Deltap=4.8 N-s` And by time averaged definition of force in case of impulse `F_("av")=(I)/(Deltat)=(Deltap)/(Deltat)=(4.80)/(0.01)=480N`

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A cricket ball of mass 150 g is moving with a speed of `12ms^(-1)` and is hit by a bat so that the ball is turned back with velocity of `20ms^(-1)` if duration of contact between bat and ball is 0.01 s then:

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