A cricket ball of mass 150 g moving with aspeed of 126km/hhitsat the middle of the bat , held firmly at its position by the batsman . The ball movesstraight back to the bowler after hitting the bat . Assuming thatcollision between ball and bat is completely elastic and the two remain in contact for 0.001s s , the force that the batsman had to apply toholdthe bat firmly at its place would be

A cricket ball of mass 150 g moving with aspeed of 126km/hhitsat the m

1.	A cricket ball of mass 150 g moving with aspeed of 126km/hhitsat the middle of the bat , held firmly at its position by the batsman . The ball movesstraight back to the bowler after hitting the bat . Assuming thatcollision between ball and bat is completely elastic and the two remain in contact for 0.001s s , the force that the batsman had to apply toholdthe bat firmly at its place would be
Answer» `10.5` N 21 N `1.05 xx10^(4) N ` `2.1 xx10^(4)`N SOLUTION :`m = 150 g = (150)/(1000)kg = 3/20 ` kg `Deltat ` = time of contact = `0.001` s u = 126 km/h = `(126 xx1000)/(60 xx60)` m/s = 35 m/s `v = - 126 km//h = - 35 m//s` Change in momentum of the BALL `Deltap = m Deltav = m(v-u)` ` =3/20 (-35 -35)`kg-m/s ` = 3/20 (-70)` `=-21/2 ` ForceF = `(Deltap)/(Deltat)` `= ((-21/2)/(0.001))N ` ` = - 0.05 xx10^(4)` N Here , -ve sign SHOWN that forcewill be opposite to the directionof motion of the ballbefore COLLISION .