1.

A cricket ball of mass 150g is moving with a velocity of 12 m/s and is hit by a bat so that the ball is turned back with a velocity ishit by a bat so that the ball is turned back with a velocity of 20 m/s. The force of blow acts for 0.01 s on the ball. What is the averate force exerted by the bat on the ball?

Answer»

240N
300N
380N
480N

Solution :The BAT exerts an impulsive FORCE on the ball.
Impulse = CHANGE in momentum
`therefore F xx t= m(v-u)`
`therefore F xx 10^(-2)= 150xx10^(-3)[ 20-(-12)]`
`therefore F = (32xx15xx10^(-2))/(10^(-2)) = 480N`


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