A cricketer bowler releases the ball in two differnet ways (a) giving it only horizontal velocity and (b) giving it horizotal velocity and a small downward velocity The speed upsilon_(s) at the time of release is the ball hits the ground ? Neglect air resistance .

A cricketer bowler releases the ball in two differnet ways (a) giving

1.	A cricketer bowler releases the ball in two differnet ways (a) giving it only horizontal velocity and (b) giving it horizotal velocity and a small downward velocity The speed upsilon_(s) at the time of release is the ball hits the ground ? Neglect air resistance .
Answer» Solution :(a) When horizontal velocity = `upsilon_(s)` and there is no DOWNWARD velocity given , As SHOWN in `upsilon_(z) = sqrt(2 g H)` `:.` velocity on hitting the ground `upsilon sqrt(upsilon_(s)^(2) + upsilon_(z)^(2)) = sqrt(upsilon_(s)^(2) + g H` (B) When horizontal velocity= `upsilon_(s)` and downward velocity= u as shown Then `u_(z) = sqrt(u^(2) + 2 gH` velocity on hitting the ground `upsilon = sqrt(upsilon_(s)^(2)+upsilon_(z)^(2)) = sqrt(upsilon_(s)^(2) + u^(2) + 2 gh)` CLEARLY `upsilon' gt upsilon` Note If u is taken as negligibly small then `upsilon = upsilon` .