1.

A cricketer can throw a ball to a maximum horizontal distance of 100m. With the same speed how much high above the ground can the cricketer throw the same ball? (a) 200m (b) 150m (c) 100m (d) 50m

Answer»

Correct answer is (d) 50m

Rmax = \(\frac{u^2}{g}\)

100 = \(\frac{u^2}{g}\) or u2 = 100g

Using, v2 = u2 + 2as

0 = (100g) + 2(-g)h or h = 50m.



Discussion

No Comment Found

Related InterviewSolutions