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A cricketer can throw a ball to a maximum horizontal distance of 100m. With the same speed how much high above the ground can the cricketer throw the same ball? (a) 200m (b) 150m (c) 100m (d) 50m |
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Answer» Correct answer is (d) 50m Rmax = \(\frac{u^2}{g}\) 100 = \(\frac{u^2}{g}\) or u2 = 100g Using, v2 = u2 + 2as 0 = (100g) + 2(-g)h or h = 50m. |
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