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A crystal is made up of metal ion M2+ and oxide ions O2- Oxide ions are in ccp lattice structure. The cation M2+ occupies half of the tetrahedral voids. If 50% of metal cations were oxidized to M3+ without disturbing the lattice of oxide ions, the total number of vacant tetrahedral voids per unit cell are |
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Answer» Number of oxide in per unit cell o-2 = 4 Number of M+2 metal per unit cell = 1/2 x θ = 4 ∵ 50% metal M+2 oxidized into M+3 ions it means , 2 metal al M+2 is oxidized into M+3 ions applying electrical Meutraility ⇒ 2 M+3 = 3 M+2 it means , on oxidation of 50% metal M+2 , or on oxidation of 2 metal of M+2 metal per unit cell. ∴ total number of metal M per unit cell = 3 ∴ number of vacant tetra hedral oxide = θ - 3 = 5 |
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