A crystal of Lead (II) sulphide has NaCl structure. In this crystal the shortest distance between the Pb^(2+) ion and S^(2-) ion is 297 pm. What is the length of the edge of the unit cell in lead sulphide ? Also calculate the unit cell volume.

A crystal of Lead (II) sulphide has NaCl structure. In this crystal th

1.	A crystal of Lead (II) sulphide has NaCl structure. In this crystal the shortest distance between the Pb^(2+) ion and S^(2-) ion is 297 pm. What is the length of the edge of the unit cell in lead sulphide ? Also calculate the unit cell volume.
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Edge 'a' of <a href="https://interviewquestions.tuteehub.com/tag/unit-1438166" style="font-weight:bold;" target="_blank" title="Click to know more about UNIT">UNIT</a> <a href="https://interviewquestions.tuteehub.com/tag/cell-25680" style="font-weight:bold;" target="_blank" title="Click to know more about CELL">CELL</a> = 2 x Distance between `Pb^(2+)` and `S^(2-)`ions .</body></html>