A cube of mass m and height H slides with a speed v. It strikes the obstacle of height h = (H/4). Find the speed of the CM of the cube just after the collision.

A cube of mass m and height H slides with a speed v. It strikes the ob

1.	A cube of mass m and height H slides with a speed v. It strikes the obstacle of height h = (H/4). Find the speed of the CM of the cube just after the collision.
Answer» SOLUTION :`MV(H/2-h)=m[((H^(2)+H^(2)))/12=(H/2)^(2)+(H/2-h)^(2)]omega` `omega=((H/2-h)v)/((H^(2))/6+(H^(2))/4+(H/2-h)^(2))` `v=romega=((H/2-h)v.sqrt((H^(2))/4+(H/2-h)^(2)))/(5/12H^(2)+(H/2-h)^(2))` If `h=H/4` we have `v'=(H/4v.sqrt((H^(2))/4+(H^(2))/16))/((5/12+1/16)H^(2))` `(v/4.sqrt(5)/4)/((15+3)/48)=(3sqrt(5))/18vimpliesv' (sqrt(5))/6v`