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A cubic lump of cheese of area 10 "cm"^2 and weight 3 N stands on a table. Calculate the pressure exerted by it on the table? |
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Answer» Solution :Force (F)=3 N, AREA (A) = `10 cm^2 = 10xx10^(-4) m^2 =10^(-3) m^2` Pressure (P)=F/A=`3N//10^(-3) m^2` `=3xx10^3` PA |
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