1.

A cubical block of iron,5 cm on each side is floating in mercury taken in a vessel. What is the height of the block above mercury level.

Answer»

SOLUTION :From the law of floatation
`V_(b)rho_(b)=V_("in")rho_(L)`
`:.(5)^(3)xx(7.2)=(5^(2)xx(13.6)`
`:.x=2.65cm`
Then the HEIGHT of the BLOCK above mercury LEVEL
`=5cm-x=2.35cm`


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