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A cubical block of iron,5 cm on each side is floating in mercury taken in a vessel. What is the height of the block above mercury level. |
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Answer» SOLUTION :From the law of floatation `V_(b)rho_(b)=V_("in")rho_(L)` `:.(5)^(3)xx(7.2)=(5^(2)xx(13.6)` `:.x=2.65cm` Then the HEIGHT of the BLOCK above mercury LEVEL `=5cm-x=2.35cm` |
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