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A cubical block of mass m is sliding on an inclined right angle trough as shown in the figure. If coefficient of friction is mu , find the acceleration of the block. |
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Answer» Solution :For the CUBICAL block , `N_(1) = N_(2) = N` RESULTANT reaction `N' = sqrt(2) N` `_|_^(ar) to JK : N' mg cos theta RARR sqrt(2) N = mg cos theta` `rArr N = (mg cos theta)/(sqrt(2))` Along the plane : `mg sin theta - mu N_(1) - mu N_(2) = ma` `mg sin theta - 2 mu N = ma` `mg sin theta - 2 mu (mg cos theta)/(sqrt(2)) = ma` ` a = g[ sin theta - sqrt(2) mu cos theta]`  
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