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A cubical block of side `a` and density `rho` slides over a fixed inclined plane with constant velocity `v`. There is a thin film of viscous fluid of thickness `t` between the plane and the block. Then the coefficient of viscosity of the thin film will be: (Acceleration due to gravity is g)A. `eta=(rhoa g t sin theta)/v`B. `(rho a g t^(2) sin theta)/v`C. `v/(rho a g t sin theta)`D. None of these |
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Answer» Viscous force `= mg sin theta` `:. Eta A v/t =mg sin theta` or `etaa^(2) v/t=a^(3) rhog sin theta` `eta=(trhog sin theta a)/v` |
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