1.

A cubical frame is made by connecting 12 identical uniform conducting rods as shown in the figure. In the steady state the temeprature of junction A is `100^(0)C` while that of the G is `0^(0)C`. ThenA. B will be Hotter than HB. Temperature of F is `40^(0)C`C. Temperature of D is `66.67^(0)C`D. Temperature of E is `50^(0)C`

Answer» Correct Answer - B
`100^(@)C-lr-(l)/(2)r-lr=0^(@)C`
`implieslr=40^(@)C,thereforet_(F)=0^(@)+lr=40^(@)C`


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