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A cuboid shaped slab of iron whose dimensions are 55 cmx40 cmx15st into a pipe. The outer diameter and thickness of the pipe are 8cm and l em0cmx15 cm is melted andrecaFind the length of the pipe. (Take π = 22 ) |
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Answer» Given,cubical shaped iron slab length=55 cmbreadth=40 cmheight=15 cmnow slab melt and form pipe outer radius of pipe=4cminner radius =(4-1)=3cmlength=?now volume of iron slab =volume of cylinder pipe => 50 x 40 x 15 =pi. {R^2-r^2}.h=> 50 x 40 x 15 =22/7 x (16-9) x h=> 50 x 40 x 15 =22/7 x 7 x hh= 50 x 40 x 15/22 cm=1363.63 cm |
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