Saved Bookmarks
| 1. |
A cuboid shaped slab of iron whose dimensions are 55 cmx40cmx15 cm is melted andrecast into a pipe. The outer diameter and thiekness of the pipe are 8cm and I am respectively.Find the length of the pipe. ( Take π = 22/7 ) |
|
Answer» Given,cubical shaped iron slab length=55 cmbreadth=40 cmheight=15 cmnow slab melt and form pipe outer radius of pipe=4cminner radius =(4-1)=3cmlength=?now volume of iron slab =volume of cylinder pipe => 50 x 40 x 15 =pi. {R^2-r^2}.h=> 50 x 40 x 15 =22/7 x (16-9) x h=> 50 x 40 x 15 =22/7 x 7 x hh= 50 x 40 x 15/22 cm=1363.63 cm |
|