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A cuboid shaped slab of iron whose dimensions are 55 cmx40cmx15 cm is melted and1 cm respectivelyrecast into a pipe. The outer diameter and thickness of the pipe are 8 cm andFind the length of the pipe. ( Take ╧А-22 ) |
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Answer» cubical shaped iron slab length=55 cmbreadth=40 cmheight=15 cmnow slab melt and form pipe outer radius of pipe=8cminner radius =(8-1)=7cmlength=?now volume of iron slab =volume of cylinder pipe => 50 x 40 x 15 =pi. {R^2-r^2}.h=> 50 x 40 x 15 =22/7 x (64-49) x h=> 50 x 40 x 15 =22/7 x 15 x hh= 50 x 40 x 15*7/22*15 cm=90.90cm^3 |
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