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A current flows through a rectangular conductor in the presence of uniform magnetic field B pointing out of the page as shown. Then the potential difference `V_(P)-V_(Q)` is equal to (assume charge carriers in the conductor to be positively charged moving with a drift velocity of v ) A. `Bvb`B. `-Bvb`C. `Bve`D. `-Bve` |
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Answer» Correct Answer - C `|epsilon|=B lv` where l is the edge perpendicular to both B and `vecv` i.e.c. `therefore |epsilon|=B v c`. Now by right hand thumb rule magnetic force an a positive charge moving towards right is in down wrd direction Hence end P will be positive. `therefore V_(P)-V_(!)` is positive `rArr epsilon=+Bvl`. |
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