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A current `i` ampere flows in a circular arc of wire whose radius is `R`, which subtend an angle `3pi//2` radian at its centre. The magnetic induction `B` at the centre is A. `(mu_(0)i)/R`B. `(mu_(0)i)/(2R)`C. `(2mu_(0)i)/R`D. `(3 mu_(0)i)/(8R)` |
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Answer» Correct Answer - D `B=(mu_(0))/(4pi)((2pi- theta)i)/R=(mu_(0))/(4pi)((2pi-pi/2)xxi)/R=(3mu_(0)i)/(8R)` |
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