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A current `i` ampere flows in a circular arc of wire whose radius is `R`, which subtend an angle `3pi//2` radian at its centre. The magnetic induction `B` at the centre is A. `mu_(0)I//R`B. `mu_(0)I//2R`C. `2mu_(0)I//R`D. `3mu_(0)I//8R` |
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Answer» Correct Answer - C For a loop, magnetic induction at centre, `B=(mu_(0))/(4pi)xx(2piI)/R` When loop subtends angle `theta` at centre, then `B=(mu_(0))/(4pi)xx(thetaI)/R` In the given problem, `theta=3pi//2` `:. B=(mu_(0))/(4pi)xx(3pi)/2xx 1/R=(3mu_(0)I)/(8R)` |
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