1.

A current `i` ampere flows in a circular arc of wire whose radius is `R`, which subtend an angle `3pi//2` radian at its centre. The magnetic induction `B` at the centre is A. `mu_(0)I//R`B. `mu_(0)I//2R`C. `2mu_(0)I//R`D. `3mu_(0)I//8R`

Answer» Correct Answer - C
For a loop, magnetic induction at centre,
`B=(mu_(0))/(4pi)xx(2piI)/R`
When loop subtends angle `theta` at centre, then
`B=(mu_(0))/(4pi)xx(thetaI)/R`
In the given problem, `theta=3pi//2`
`:. B=(mu_(0))/(4pi)xx(3pi)/2xx 1/R=(3mu_(0)I)/(8R)`


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