A current is passed through two cells connected in series. The first cell contians `X(NO_(2))_(2)`(aq). The relative atomic masses of X and Y are in the ratio 1:2. What is the ratio of the liberated mass of X to that of Y ?A. `3:2`B. `1:2`C. `1:2`D. `3:3`

A current is passed through two cells connected in series. The first c

1.	A current is passed through two cells connected in series. The first cell contians `X(NO_(2))_(2)`(aq). The relative atomic masses of X and Y are in the ratio 1:2. What is the ratio of the liberated mass of X to that of Y ?A. `3:2`B. `1:2`C. `1:2`D. `3:3`
Answer» Correct Answer - C (c ) The oxidation states of X and Y in their respective nitrates are 3 and 2 respectively. The equivalent masses of the metals can be calculated by dividing the respective atomic masses with oxidation states or valences. These are in the ratio `1//3 : 2//2` or `1//3 : 1` or `1:3`

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A current is passed through two cells connected in series. The first cell contians `X(NO_(2))_(2)`(aq). The relative atomic masses of X and Y are in the ratio 1:2. What is the ratio of the liberated mass of X to that of Y ?A. `3:2`B. `1:2`C. `1:2`D. `3:3`

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