A current is passed through two cells connected in series. The first cell contains `X(NO_(3))_(3(aq))` and the second cell contains `Y(NO_(3))_(2(aq))`. The relative atomic masses of X and Y are in the ratio 1:2. What is the ratio of liberated mass of X to that of Y.A. `3:2`B. `1:2`C. `1:3`D. `3:1`

A current is passed through two cells connected in series. The first c

1.	A current is passed through two cells connected in series. The first cell contains `X(NO_(3))_(3(aq))` and the second cell contains `Y(NO_(3))_(2(aq))`. The relative atomic masses of X and Y are in the ratio 1:2. What is the ratio of liberated mass of X to that of Y.A. `3:2`B. `1:2`C. `1:3`D. `3:1`
Answer» Correct Answer - C The oxidation states of X and Y are `X^(3+) and Y^(2+)` given atomic masses are in the ratio of 1:2 `therefore` Equivalent masses are in the ratio `(1)/(3):(2)/(2)` or `(1)/(3):1` or `1:3`

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A current is passed through two cells connected in series. The first cell contains `X(NO_(3))_(3(aq))` and the second cell contains `Y(NO_(3))_(2(aq))`. The relative atomic masses of X and Y are in the ratio 1:2. What is the ratio of liberated mass of X to that of Y.A. `3:2`B. `1:2`C. `1:3`D. `3:1`

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