1.

A current liberates 0.504 g of hydrogen in 2 hours, the amount of copper lib erated from a solution `CuSO_(4)` by the same current flowing for the same time would beA. 31.8gB. 63.6gC. 15.9gD. 6.36g

Answer» Correct Answer - A
g eq. of hydrogen =g eq. of Cu
`(0.504)/(1)=(W)/(63.5//2) therefore W=15.9g`


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