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A current loop `ABCD` is held fixed on the plane of the paper as shown in figure. The arcs `BC( radius = b) and DA ( radius = a)` of the loop are joined by two straight wires `AB and CD` at the origin `O` is 30^(@)`. Another straight thin wire with steady current `I_(1)` flowing out of the plane of the paper is kept at the origin . The magnitude of the magnetic field (B) due to the loop `ABCD` at the origin (o) is :A. `(mu_(0)I)/(4pi)[[b-a)/(ab)]`B. `(mu_(0)I)/(4pi) [2(b-a) + (pi)/(3) (a +b)]`C. zeroD. `(mu_(0)I(b-a))/(24ab)` |
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Answer» Correct Answer - 2 Magnetic filed due to loop `ABCD` `= (mu_(0)I)/(4pi)((pi)/(6)) xx [(1)/(a) - (1)/(b)] = (mu_(0)I)/(24) [(b-a)/(ab)]` . |
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