A current loop `ABCD` is held fixed on the plane of the paper as shown in figure. The arcs `BC( radius = b) and DA ( radius = a)` of the loop are joined by two straight wires `AB and CD` at the origin `O` is 30^(@)`. Another straight thin wire with steady current `I_(1)` flowing out of the plane of the paper is kept at the origin . The magnitude of the magnetic field (B) due to the loop `ABCD` at the origin (o) is :A. zeroB. `(mu_(0)(b-a)i)/(24ab)`C. `(mu_(0)I)/(4pi)[(b-a)/(ab)]`D. `(mu_(0)I)/(4pi)[2(b-a)+(pi)/(3)[a+b)]`

A current loop `ABCD` is held fixed on the plane of the paper as shown

1.	A current loop `ABCD` is held fixed on the plane of the paper as shown in figure. The arcs `BC( radius = b) and DA ( radius = a)` of the loop are joined by two straight wires `AB and CD` at the origin `O` is 30^(@)`. Another straight thin wire with steady current `I_(1)` flowing out of the plane of the paper is kept at the origin . The magnitude of the magnetic field (B) due to the loop `ABCD` at the origin (o) is :A. zeroB. `(mu_(0)(b-a)i)/(24ab)`C. `(mu_(0)I)/(4pi)[(b-a)/(ab)]`D. `(mu_(0)I)/(4pi)[2(b-a)+(pi)/(3)[a+b)]`
Answer» Correct Answer - C Net magntic field due to loop `ABCD` at `O` is `B=B_(AB)+B_(BC)+B_(CD)+B_(DA)` `B=0+(mu_(0)I)/(4pia)xx(pi)/(6)+0-(mu_(0)I)/(4pib)xx(pi)/(6)`

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