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A current of 0.01 mA passes through the potentiometer wire of a resistivity of `10^(9)Omega` cm and area of cross-section `10^(-1) cm^(-2)` . The potential gradient isA. `10^(9) V/m`B. `10^(11) V/m`C. `10^(10) V/m`D. `10^(8) V/m` |
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Answer» Correct Answer - D Potential gradient is given by `k=(V)/(l)=(lR)/(l) " " (because V = lR)` `= (l xx rho l// A)/(l) " " (because R = (rho l)/(A))` `therefore k = (0.01xx10^(-3)xx10^(9)xx10^(-2))/(10^(-2)xx10^(_4))=10^(8) V//m` |
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